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![What will be the pressure in dyne cm^-2 , due to a water column of height 10cm ? [take g = 980cm/s^2 ] (density of water = 10^3kg m^-3 ).](https://dwes9vv9u0550.cloudfront.net/images/2485706/ed4284a0-8615-4be0-9398-e2024f567486.jpg "What will be the pressure in dyne cm^-2 , due to a water column of height 10cm ? [take g = 980cm/s^2 ] (density of water = 10^3kg m^-3 ).")
What will be the pressure in dyne cm^-2 , due to a water column of height 10cm ? [take g = 980cm/s^2 ] (density of water = 10^3kg m^-3 ).
A body of mass m is floating in a liquid of density d.a) What is the apparent weight of the body?b) What is the loss of weight of the body?
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The value of universal gravitational cosntant G in CGS system is 6.67 × 10^-8 dyne cm^2gm^-2 . Its value in SI system is :
A force of 10 N acts on a body of 2 kg mass for a distance of 1 m. The kinetic energy received by the body is:
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The value of G = 6.67 × 10^-10Nm^2(kg)^-2 its numerical value in CGS system will be
Turiform Kugle- /vægtdyne | Junior dyne | 2 kg mikro glaskugler | 100x140
Turiform Kugle- /vægtdyne | Junior dyne | 2 kg mikro glaskugler | 100x140
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A sphere of mass 2000 g and radius 5 cm is rotating at the rate of 300 rpm . Then the torque required to stop it in 2pi revolutions, is
The value of gravitation is `G = 6.67 xx 10^(-11)N-m^(2)/kg^(2)` in SL units . Convert it into C... - YouTube
A pressure of `10^(6)" dyne"//cm^(2)` is equivalent to : - YouTube
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NEWTON'S SECOND LAW NUMERICAL PROBLEMS
